If SID is 60 inches and SOD is 45 inches, what is the magnification factor?

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Multiple Choice

If SID is 60 inches and SOD is 45 inches, what is the magnification factor?

Explanation:
In radiography, the magnification factor is the ratio of the distance from the X-ray source to the image receptor (SID) to the distance from the source to the object (SOD). It shows how much larger the image will appear than the actual object. With SID = 60 inches and SOD = 45 inches, the magnification factor is 60/45 = 1.33, so the image is about 1.33 times the size of the object. This happens because the farther the receptor is from the source relative to the object, the more the image is magnified.

In radiography, the magnification factor is the ratio of the distance from the X-ray source to the image receptor (SID) to the distance from the source to the object (SOD). It shows how much larger the image will appear than the actual object. With SID = 60 inches and SOD = 45 inches, the magnification factor is 60/45 = 1.33, so the image is about 1.33 times the size of the object. This happens because the farther the receptor is from the source relative to the object, the more the image is magnified.

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