If a wall experiences the same ΔT, what is the conduction rate change when the area is doubled and the thickness is halved?

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Multiple Choice

If a wall experiences the same ΔT, what is the conduction rate change when the area is doubled and the thickness is halved?

Explanation:
The rate of heat conduction through a wall at a fixed temperature difference is proportional to A/L (Area over Thickness) for a given material. Doubling the area increases the available path for heat, while halving the thickness halves the distance heat must travel, effectively increasing the rate by a factor of two again. Put together, the new rate is (2A) / (L/2) = 4(A/L). So the conduction rate becomes four times larger.

The rate of heat conduction through a wall at a fixed temperature difference is proportional to A/L (Area over Thickness) for a given material. Doubling the area increases the available path for heat, while halving the thickness halves the distance heat must travel, effectively increasing the rate by a factor of two again. Put together, the new rate is (2A) / (L/2) = 4(A/L). So the conduction rate becomes four times larger.

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